The circle passin through the point (-1,0) and touching the y- axis at (0,2) also passes through the point
a) (-3/2 , 0) b) (-5/2 , 2) c) (-3/2 , 5/2 ) d) (-4 , 0 )
Dear student
Circle touching y-axis at (0, 2) is (x - 0)2 + (y - 2)2 + ax = 0
It passes through (- 1, 0)
So, 1 + 4 - a = 0
It passes through (- 1, 0)
So, 1 + 4 - a = 0
This gives a = 5
So, the equation of the cirlce is
x2 + y2 + 5x - 4y + 4 = 0
Put y = 0 x = - 1, - 4
So, Circle passes through (- 4, 0)
So, d) is the correct option.
Regards
Put y = 0 x = - 1, - 4
So, Circle passes through (- 4, 0)
So, d) is the correct option.
Regards