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The circle passin through the point (-1,0) and touching the y- axis at (0,2) also passes through the point

a) (-3/2 , 0) b) (-5/2 , 2) c) (-3/2 , 5/2 ) d) (-4 , 0 )

Circle touching y-axis at (0, 2) is (x - 0)

It passes through (- 1, 0)

So, 1 + 4 - a = 0

^{2}+ (y - 2)^{2}+ ax = 0It passes through (- 1, 0)

So, 1 + 4 - a = 0

This gives a = 5

So, the equation of the cirlce is

x

Put y = 0 x = - 1, - 4

So, Circle passes through (- 4, 0)

So, d) is the correct option.

Regards

^{2}+ y^{2}+ 5x - 4y + 4 = 0Put y = 0 x = - 1, - 4

So, Circle passes through (- 4, 0)

So, d) is the correct option.

Regards

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