the cofficent of x30 in (3x2+ 2/3x2)15 is Share with your friends Share 2 Lovina Kansal answered this Dear student Suppose r+1th term involves x30 in the expansion of 3x2+23x215Now, Tr+1=15Cr3x215-r23x2r=15Crx30-3r3152r ...(1)For this term to contain x30, we must have30-3r=30r=0So, (0+1)th i.e 1th term contains x30.Putting r=0 in (1), we getT1=15C1x3031520=15×315x30∴Coefficient of x30=15×315 Regards -4 View Full Answer
