The compound contains 2.13% of hydrogen 12.76% of carbon and 85.11% of bromine. Its molar mass is 188g. What is the empirical and molecular formula?

Dear Student,

 Element % At. mass Relative no. of atoms Simplest ratio C 12.76 12 $\frac{12.76}{12}=1.06$ $\frac{1.06}{1.06}=1$ Br 85.11 80 $\frac{85.11}{80}=1.06$ $\frac{1.06}{1.06}=1$ H 2.13 1 $\frac{2.13}{1}=2.13$ $\frac{2.13}{1.06}=2$

The empirical formula is CH2Br

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