The condition that the chord xcos a + ysin a - p = 0 of x2 + y2 = a2 may subtend a right angle at the centre of the circle is

Best Answer xcosα + ysinα = p The perp ON from O to line has length |0+0−p|/√(cos²α+sin²α) = |p| If chord of intersection AB subtends 90° at centre then ∠NOB=45° From ΔNOB, cos(45°) = |p|/a → a=|p|√2 or a²=2p²
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