The contents of three bags I, II and III are as follows :
Bag l : 1 white, 2 black and 3 red balls.
Bag II : 2 white, I black and 1 red ball.
Bag III : 4 white , 5 black and 3 red balls.
A bag is chosen at random and two balls are drawn. What is the probability that the balls are white and red ?

Let us deine the events :E1 : Bag 1 is chosenE2 : Bag 2 is chosenE3 : Bag 3 is chosenA : both the balls drawn are white and red.PE1 = PE2 = PE3  = 13PA/E1 = C11 × C13C26 = 315PA/E2 = C12 × C11C24 = 26PA/E3 = C14 × C13C212 = 1266Now, PA =PE1 ×  PA/E1 +  PE2 × PA/E2 + PE3 × PA/E3=13×315 + 13×26 + 13×1266=115 + 19 + 233=33 + 55 + 30495=118495

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