the coordinates of A,B,C are (3,4) (5,2) and (x,y) respectively. if area of triangle ABC = 3, show that x+y = 10

A(3,4) ; B(5, 2); C(x, y)ar. ABC = 312{3(2-y) + 5(y - 4) + x(4 - 2)} = 33(2-y)+5(y-4)+2x = 66 - 3y +5y - 20 + 2x = 62y + 2x = 20x +y = 10Hence proved!

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