The coordinates of three points O,A,B are (0,0), (0,4), (6.0) respectively. A point P moves so that the area of the triangle POA is twice the area of the traingle POB. Find the equation to both parts of the locus of P. 

 

The three given points are origin, one on x -axis and other on y - axis.

Let the coordinates of P be (x, y)

 

we know that area of triangle =

 

Now Δ POA = Δ POB

⇒ 2x = ± 6y

x = ± 3y

 

Hence the required locus of both parts is (x – 3y) (x + 3y) = 0

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