The correct order of increasing solubility of AgCl in (A)Water (B)0 1M NaCl (C) 0 1 M BaCl2 (D)0 1 - Chemistry - Chemical and Ionic Equilibrium

Question

The correct order of increasing solubility of AgCl in (A)Water (B)0
1M NaCl (C) 0 1 M BaCl2 (D)0 1 M NH3

Yasodharan · Accepted Answer

Dear Student,

The computation for correct order is as expressed below,

in water⇒ [Cl-] = 0in NaCl ⇒ [Cl-]  = 0
1 Min BaCl2 ⇒ [Cl-]  = 0
2 Min NH3, Ag+ forms complex ion ⇒ Ag+ + 2NH3 ⇋ [Ag(NH3)2]+hence the answer will be0
1 M BaCl2 < 0
1 M NaCl < Water < 0
1 M NH3
C < B < A < D

Regards

The correct order of increasing solubility of AgCl in (A)Water (B)0.1M NaCl (C) 0.1 M BaCl2 (D)0.1 M NH3