The correct order of increasing solubility of AgCl in (A)Water (B)0.1M NaCl (C) 0.1 M BaCl2 (D)0.1 M NH3

Dear Student,

The computation for correct order is as expressed below,

in water [Cl-] = 0in NaCl  [Cl-]  = 0.1 Min BaCl2  [Cl-]  = 0.2 Min NH3, Ag+ forms complex ion  Ag+ + 2NH3  [Ag(NH3)2]+hence the answer will be0.1 M BaCl2 < 0.1 M NaCl < Water < 0.1 MNH3
C < B < A < D

Regards.

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