The coulombs of energy required for reduction of 1 mole of H2O2 to O2 is ?

Dear Student,

According to the question,H2O2  2H+ + O2H2O2 to O2 is not reduction, it is oxidation as here loss of electron (-1 to 0) is taking place.2O-  O2 + 2e-Electricity required for the oxidation of 1 mol of H2O2 to O2= nF                                                                                                      =2 ×96500 Coulumbs                                                                                                      =1.93×105 Coulumbs                                          

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