. The decomposition of  N 2 O 5  in  C C I 4 in  C C l 4  solution follows the first order rate law. The concentration of N 2 O 5   N 2 O 5  measured at different time intervals are given below  
Time in seconds (t) 0 80 160 410 600 1130 1720
N 2 N 2 O 5 O 5 (mol/L) 5.5 5.0 4.8 4.0 3.4 2.4 1.6

Calculate its rate constant at t= 410 s and t = 1130 s. What do these results show?

Dear Student,
The equation for the first-order reaction is K=2.303tlogaa-xAt t=410 s,  a=5, a-x=4K = 2.303410log5.54=0.0056(1.7404 -1.6021) =7.7 x 10-4 s-1At t =1130 s,K = 2.303410log5.54=7.34 x 10-4 s-1

The rate constant for both the reactions is nearly the same.There is negligible difference.
Since the rte constant is the same, this shows that this is a first order reaction.

Hope it helps.

Regards
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