The decomposition of PH3 proceeds according to the following equation

4PH3(g)-----------------> P4(g) + 6H2(g)

rate=k[PH3] , t1/2=37.9 s at 120 degrees

how much time is required for 3/4th of PH3 to decompose?

What is the concentration of PH3 after 1 min?

Question

The decomposition of PH3 proceeds according to the following
equation
4PH3(g)-----------------> P4(g) + 6H2(g)
rate=k[PH3] , t1/2=37 9 s at 120 degrees
how much time is required for 3/4th of PH3 to decompose?
What is the concentration of PH3 after 1 min?

Naveen Rawat · Accepted Answer

$t_{1 / 2} = 0 693 / k k = 0 693 / 37 9$ $k = 0 0183 \sec^{- 1}$ $1 / c = 1 / c_{o} + k t a t, t_{1 / 2} c = c_{o} / 2 2 / c_{o} = 1 / c_{o} + k t_{1 / 2} 1 / c_{o} = k t_{1 / 2} c_{o} = 1 / k t_{1 / 2} c_{o} = 1 / 0 6936 c_{o} = 1 44$ Time at 3/4 of PH3 decompose, $a t t_{3 / 4}, c = 1 08 a n d c_{o} = 1 44 1 / c = 1 / c_{o} + k t 1 / 1 08 = 1 / 1 44 + 0 0183 t_{3 / 4} 1 / 1 08 - 1 / 1 44 = 0 0183 t_{3 / 4} 0 93 - 0 69 = 0 0183 t_{3 / 4} t_{3 / 4} = 0 24 / 0 0183 t_{3 / 4 = 13 12}$ $t_{3 / 4 = 13 12 \sec}$ Concentration after one minute $1 \min = 60 \sec 1 / c = 1 / c_{o} + k t 1 / c = 1 / 1 44 + 0 0183 * 60 1 / c = 1 788 c = 1 / 1 788 c = 0 559$

The decomposition of PH3 proceeds according to the following equation 4PH3(g)-----------------> P4(g) + 6H2(g) rate=k[PH3] , t1/2=37.9 s at 120 degrees how much time is required for 3/4th of PH3 to decompose? What is the concentration of PH3 after 1 min?

The decomposition of PH3 proceeds according to the following equation

4PH3(g)-----------------> P4(g) + 6H2(g)

rate=k[PH3] , t1/2=37.9 s at 120 degrees

how much time is required for 3/4th of PH3 to decompose?

What is the concentration of PH3 after 1 min?