the denominator is one more than  twice  the numerator , if the sum of the fraction and  its recoprocal is 2  16/21 . find the fraction

let the numerator be 'x' then denominator is'2x+1'

given="x / 2x+1" + "2x+1/x"=2 16/21

then="x / 2x+1" + "2x+1/x"=58/21

=x(x)+2x+1(2x+1) / 2x+1(x=58/21

=x2+(2x+1)2  / 2x2+x=58/21

=x2+4x2+4x+1 / 2x2+x=58/21

=5x2 +4x+1 / 2x2+x=58/21

=5x2 +4x+1(21)=58(2x2+x)

=105x2 +84x+21=116x2 +58x

=116x2 +58x-105x2 -84x-21=0

=11x- 26x-21=0

by solving using x= -(b)+rootb2 -4ac /2a

we get x=3 so the fraction is 3/7

check

3/7 +7/3 =49 +9 /21=58 /21

hence verified

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sdskkj
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fyuiuoipo[l
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ytrd
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kasangmitah
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kamsangmitah*
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dude x=3/2 then only u will get the answer as 3/7. and if x=3 the answer is 3/5
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674376764
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3/7
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A.T.Q
11x^2-26x-21=0
then x=3
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The answer is
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The answer is 3/7

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3/7 is the fraction
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thumbs up!!!
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tu6ttot795
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3/7 
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