the derivative of sin3x.cos3x ?

Dear student,

Please find below the solution to the asked query:

Consider the following function.   y=sin3x·cos3xUse product rule to differentiate the above function.    u·v'=u'·v+u·v'This implies that,  dydx=cos3x·ddxsin3x+sin3x·ddxcos3x         =cos3x·3 sin2x ddxsinx+sin3x· -sin3xddx3x         =3 cos3x sin2x cosx-sin3x sin3x ·3         =3cos3x sin2x cosx-3sin3x sin3x

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