​The diagonal of a rectangle ABCD intersect at O. If BOC = 76 , find ODA​


Given in rectangle ABCD, ∠BOC = 76°
∠BOC = ∠AOD  [Vertically opposite angles are equal]
∠AOD = 76°
Since diagonal of a rectangle are equal and they bisect each other.
We can write OA = OB = OC = OD
Hence DAO is an isosceles triangle.
⇒∠OAD = ∠ODA  [Angles opposite to equal sides of a triangle are equal]
Let ∠OAD = ∠ODA = x
∠OAD + ∠ODA +∠AOD = 180°
 ⇒ x + x + 76° = 180°
⇒ 2x = 104°
 ⇒ x = 52°
Hence ∠ODA = 52°

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