The diagonals a rectangle ABCD intersect at a point O. If angle COD =78 then find the value of angle OAB

IF COD IS 78 THEN AOB WILL ALSO BE 78 (VERTICALLY OPPOSITE ANGLES)
DIAGONALS OF A RECTANGLE ARE EQUAL AND BISECT EACH OTHER
SO OAB + AOB +OBA = 180
OAB + OBA =102 
2OAB = 102                                   (OBA=OAB)
OAB = 51

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