The diagonals of a parallelogram PQRS are along the lines x+3y=4 and 6x-2y=7. Then PQRS is aA) Rectangle B) Square C) Cyclic Quadrilateral D) RhombusThe answer is option 'D' but my doub't is why can't it be square.please explain it as fast as u can my exam is with in four days
The slope of x +3y = 4 is 1/3
And 6x -2y = 7 is -3
So the product of the slope is 1/3 *(-3) = -1
Hence the diagonals are perpendicular to each other.
Here the answer option can be rhombus as well as square , but in rhombus the diagonals are unequal so it is more closer option. And nothing is mentioned about diagonals.
And 6x -2y = 7 is -3
So the product of the slope is 1/3 *(-3) = -1
Hence the diagonals are perpendicular to each other.
Here the answer option can be rhombus as well as square , but in rhombus the diagonals are unequal so it is more closer option. And nothing is mentioned about diagonals.