The difference of 2 complementary angles is 30 degree. Then the angles are
Dear student
Let one angle =x
So, other angle =90°-x
A.T.Q
x-(90°-x)=30°
x-90°+x=30°
2x=30°+90°
2x=120°
x=60°
So, angles are 60° and 90°-60°=30°
Regards
Let one angle =x
So, other angle =90°-x
A.T.Q
x-(90°-x)=30°
x-90°+x=30°
2x=30°+90°
2x=120°
x=60°
So, angles are 60° and 90°-60°=30°
Regards