the difference of two numbers is 5 and the difference of their reciprocals is 1/10. find the no.s.....

plz show wid procedure.... answer is not comin..

Let the two numbers be x and x – 5.

According to the question,

x (x – 5) = 50

x2 – 5x – 50 = 0

x2 – 10x + 5x – 50 = 0

x (x – 10) + 5 (x – 10) = 0

⇒ (x + 5) (x – 10) = 0

⇒ (x + 5) (x – 10) = 0

x = – 5  or 10

x = 10 (x = – 5, rejected)

∴ Two numbers are 10 and (10 – 5) = 5.

  • 122

Let the greater  number b x

then, the other=x-5

from the given details

1/x-5  -  1/x=1/10

ie x-(x-5)/ x(x-5)=1/10

ie  5/ (x2 -5x)=1/10

cross multiplying,we get

x2-5x=50

x2 -5x-50=0

now proceed

  • 2

why x-5 why  not  5-x?

  • -6

if the 2 numbers are xand y

then x-y=5

ie y=x-5

if the other number is 5-x then

5-x=-y

that is y

  • 1

that is 'y' means that is whyyyyyy

  • -11
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