The digit in the tens place of a number consisting of two digits is greater than that in the units place by 7.The sum of digits 1/9th of the number.Find the number.

Let the digit at units place = xLet the digit at tens place = yNow, original number = 10y + xNow, according to first condition :y = x + 7     ......1according to second condition :x + y = 1910y + x9x + 9y = 10y + xy = 8x    .....2From 1 and 2, we get8x = x + 77x = 7x = 1Now, from 1, we gety = 1 + 7 = 8Now, original number = 10 × 8 + 1 = 81 

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