The distance between the circumcenter and the orthocenter of triangle ABC with the vertices A(2,1,5)B(3,2,3)C(4,0,4)

42. The distance between the circumcentre and the orthocentre of ΔABC with vertices A(2, 1, 5), B(3, 2, 3), C(4, 0, 4)

$$\begin{gathered} \left(1\right) \sqrt{6} \\ \left(2\right) \frac{\sqrt{6}}{2} \\ \left(3\right) 2\sqrt{6} \\ \left(4\right) 0 \end{gathered}$$