the distance between the foci is 4root13 and the length of conjugate axis is 8 then the eccentricity of the hyperbola is Share with your friends Share 0 Mayank Jha answered this Dear student, Given, Length of conjugate axis = 8 unit = 2b⇒b = 82 = 4 unitDistance between the foci = 413 unit = 2c⇒c = 4132 = 213 unitWe know that, a = c2 - b2 = 52 - 16 = 36 = 6 unitThus, Eccentricity of the hyperbola will be = 1 + b2a2 = 1 + 1636 = 1 + 49 =133 Regards 1 View Full Answer