The distance between the nearest neighbours in cesium chloride crystal will be?

Dear Student,

CsCl has body centred cubic cell i.e. it is bcc. Now, for bcc, distance between nearest neighbour is given by
$\mathrm{Distance} \mathrm{between} \mathrm{nearest} \mathrm{neighbour}=\frac{\mathrm{a}\sqrt{3}}{2}$