the distance between the parallel lines 9x2-24xy+16y2-12x+16y-12=0 is Share with your friends Share 6 Rahul Raj answered this Dear student 9x2-24xy+16y2-12x+16y-12=0(3x)2-2.3x.4y+(4y)2-4(3x-4y)-12=0(3x-4y)2-4(3x-4y)-12=0(3x-4y)2-6(3x-4y)+2(3x-4y)-12=0(3x-4y)(3x-4y-6)+2(3x-4y-6)=0(3x-4y-6)(3x-4y+2)=0so lines are 3x-4y-6=03x-4y+2=0distance=6-(-2)32+42=85 Regards 12 View Full Answer Aditi Sharma answered this dassad -1
