the distance between the points (a cos theta + b sin theta , 0) and (0, a sin theta - b cos theta) is A) a2 + b2 B) a + b C) a2 - b2 D) root of (a2 + b2) Share with your friends Share 17 Varun.Rawat answered this We know that distance between 2 points x1, y1 and x2, y2 is given by :distance = x2-x12+y2-y12Now, distance between a cos θ + b sin θ, 0 and 0, a sin θ - b cos θ isdistance = 0-a cos θ - b sin θ2 + a sin θ - b cos θ - 02=a2cos2θ+b2sin2θ+ 2 ab sin θ . cos θ+a2sin2θ+b2cos2θ- 2 ab sin θ . cos θ =a2sin2θ + cos2θ+ b2sin2θ + cos2θ=a2+b2 as, sin2θ + cos2θ = 1 43 View Full Answer