the distance covered by the body to come to test when it is moving with a speed of 4m/s is s when a retarding force F is applied. if KE is doubled the distance covered by it to come to rest for same retarding force F is Share with your friends Share 5 Roop Narayan answered this Dear studentassuming that the mass of the body is ma=Fmv2-u2=2as0-42=2Fmss=-8mFKE initially= 12mv2=12m42=8m2KE=16m16m=12mvnew2vnew=32v2-u2=2asnew0-32=2Fmsnewsnew=-16mFso, double distance will be covered in the second caseRegards 8 View Full Answer
