the distance moved by a student at a different intervals of time, while walking to school, is given in the table below
t(s) 0 10 20 30 40 50
s(m) 0 15 30 45 30 60
draw speed time graph for the motion of the student what does the shape of the graph suggest about the type of motion?
Since, speed = Distance/ Time.
Therefore, the speed for the case 1 at t= 0 and s = 0 m will be v1 = 0/0 = 0 m/s
Similarly,speed for the case 2, 3, 4, 5 and 6 will be 1.5 m/s, 1.5 m/s, 1.5 m/s,0.75 m/s and 1.2 m/s respectively. It is also shown in the table given below :
Time (s) | 0 | 10 | 20 | 30 | 40 | 50 |
Distance (m) | 0 | 15 | 30 | 45 | 30 | 60 |
Speed (m/s) | 0 | 1.5 | 1.5 | 1.5 | 0.75 | 1.2 |
The speed - time graph will be as shown :
From graph, we find that the from point A to point B, the student moves with constant speed and from point O to A, he is moving with positive acceleration.