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The eccentricity of the earth's orbit is e. What is the rati of its maximum speed to its minimum speed?

The eccentricity of the earth's orbit is 0.0167. The ratio of its maximum speed in its orbit to its minimum speed is 1.033.
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1.033
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Its like if eccentricity (e) is given, you can give maximum speed/minimum speed = (1+e)/(1-e) 

so here the required ratio is (1+0.0167)/(1-0.0167) = 1.033 

Hope anyone who reads this answer understands......

 
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The ratio of its maximum and minimum speeds in this orbit will be 1.033
Explanation:

According to the law of conservation of angular momentum.

mv1r1 = mv1r2

The ratio between speed.

V(max) / V(min) = 1+e / 1−e

                         = 1 + 0.0167 / 1 − 0.0167

                         = 1.0167 / 0.9833

                         = 1.033

Thus The ratio of its maximum and minimum speeds in this orbit will be 1.033
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