# the efficiency of a carnot engine having source temperature 127c and sink 27 c is

The computation for the carnot efficiency is expressed below,

$Givendata,\phantom{\rule{0ex}{0ex}}Sourcetemperature\left(T\right)={127}^{o}C=400K\phantom{\rule{0ex}{0ex}}Sinktemperature\left(t\right)={27}^{o}C=300K\phantom{\rule{0ex}{0ex}}\phantom{\rule{0ex}{0ex}}\eta =\frac{T-t}{T}\times 100\%\phantom{\rule{0ex}{0ex}}\eta =\frac{400-300}{400}\times 100\%=\frac{1}{4}\times 100\%\phantom{\rule{0ex}{0ex}}\eta =25\%$

Hence the efficiency of carnot engine is 25%

Regards.

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