The electric potential V(x) in a region along the X-axis varies with the distance x(in m)
according to the relation V(x) = 4x2. Calculate the force experienced by a 1microC charge placed at point x = 1 m.
Given, V=4x^2
Now, E = dV/dx =8x
Therefore, at x=1, E=8*1 = 8
So,F = q E =10^(-6) * 8 = 8 *10^(-6) = 8 microN
Now, E = dV/dx =8x
Therefore, at x=1, E=8*1 = 8
So,F = q E =10^(-6) * 8 = 8 *10^(-6) = 8 microN