The EMF of the cell Ag|AgCl, 0 05M KCl || 0 05M AgNO3|Ag is 0 788 Volt Find the - Chemistry - Electrochemistry

Question

The EMF of the cell Ag|AgCl, 0 05M KCl || 0 05M AgNO3|Ag is 0 788
Volt Find the solubility product of AgCl Please give deatailed
solutions ans is 1 16 * 10^(-16) M^2 model paper iitjee

Tejan_1 · Accepted Answer

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The EMF of the cell Ag|AgCl, 0.05M KCl || 0.05M AgNO3|Ag is 0.788 Volt. Find the solubility product of AgCl. Please give deatailed solutions. ans is 1.16 * 10^(-16) M^2 model paper iitjee