The enthalpy of solution of BaCl2 (s) and BaCl2 2H2O(s) is x kJ mol 1 and y kJ mol - Chemistry - Thermodynamics

Question

The enthalpy of solution of BaCl2 (s) and
BaCl2 2H2O(s) is –x kJ
mol–1 and y kJ mol–1 respectively
then enthalpy of hydration of BaCl2(s) to
BaCl2 2H2O(s) is given by
(1) (x – y) kJ (2) (y – x) kJ (3) (x + y) kJ (4)
–(x + y) kJ

Vartika Jain · Accepted Answer

Dear Student,

Enthalpy of hydration= Enthalpy of solution of BaCl2-enthalpy of solution of BaCl2
2H2O                                     =-x-y                                     =-(x+y) kJ/molHence, correct ansnwer is (4)

The enthalpy of solution of BaCl2 (s) and BaCl2.2H2O(s) is –x kJ mol–1 and y kJ mol–1 respectively then enthalpy of hydration of BaCl2(s) to BaCl2.2H2O(s) is given by (1) (x – y) kJ (2) (y – x) kJ (3) (x + y) kJ (4) –(x + y) kJ

The enthalpy of solution of BaCl₂ (s) and BaCl₂.2H₂O(s) is –x kJ mol^–1 and y kJ mol^–1 respectively then enthalpy of hydration of BaCl₂(s) to BaCl₂.2H₂O(s) is given by
(1) (x – y) kJ (2) (y – x) kJ (3) (x + y) kJ (4) –(x + y) kJ