The eqivalent weight of a metal in different compounds is 18.6 and 28. Atomic mass of the metal would be
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Please find the solution to the asked query:
Equivalent weight of metal in first compound is 18.6.
Equivalent weight of metal in second compound is 28.
The ratio of its equivalent weight in both the compounds is 18.6 : 28.
Thus the approximate ration is 0.5 : 1
Converting into whole number ratio, we get 1:2
i.e valency can be equal to 2
so atomic weight of metal is equal to equivalent weight ×valency. then atomic weight =18.6×2=37.2
Hope this information will clear your doubts regarding the topic. If you have any other doubts please ask here on the forum and our experts will try to solve them as soon as possible.
Regards
Please find the solution to the asked query:
Equivalent weight of metal in first compound is 18.6.
Equivalent weight of metal in second compound is 28.
The ratio of its equivalent weight in both the compounds is 18.6 : 28.
Thus the approximate ration is 0.5 : 1
Converting into whole number ratio, we get 1:2
i.e valency can be equal to 2
so atomic weight of metal is equal to equivalent weight ×valency. then atomic weight =18.6×2=37.2
Hope this information will clear your doubts regarding the topic. If you have any other doubts please ask here on the forum and our experts will try to solve them as soon as possible.
Regards