The equation - 3 has (log, x (c) Two real solutions (a) integral solution (b) Three real solutions (d) One - Maths - Linear Inequalities

Question

The equation - 3 has (log, x (c) Two real solutions (a) integral
solution (b) Three real solutions (d) One irrational solution If
log, b +log, C+ log, a vanishes, where a b and c are positive real
and to 1, then the (og, b)(log, c(log, a) IS (b) 2 (a) 1 (d) 4 (c)
3 logx logy logz y Z Z X 10 if y then the value of xyz - (a) 0 (b)
(d) 1 (c) 2 Ix+x-2/x- (a) O 17 2, number of solutions are:- (b) 1
(c) 2 (d) 4 (d) (d) 12 ifIx-3/+Ix-5- 2x-8, then the number of
solution of the equation are 13 IfIx24x3/-x2 4x+ 3, then x belongs
to (a) O (b) 1 (c) 2 (a) R (b) (-oo,1] [3, co) (b) [3,co) ats Roots
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Zuhaib Ul Zamann · Accepted Answer

Dear student,
x2-4x+3=x2-4x+3i
e t=t  where t=x2-4x+3which is true if t≥0i
e x2-4x+3≥0(x-3)(x-1)≥0which is true if both (x-3) and x-1 are non-positive or non-negativeCase I:- Both are non-positivex-3≤0  and x-1≤0i
e x≤3 and x≤1⇒x≤1Case II Both are non-negativex-3≥0 and x-1≥0x≥3 and x≥1⇒x≥3Hence x∈(-∞,1]∪[3,∞)Regards