The equation for the action of heat on calcium nitrate: - 2Ca (NO3) -- 2CaO + 4NO2 + - Chemistry -

Question

The equation for the action of heat on calcium nitrate: - 2Ca
(NO3) -- > 2CaO + 4NO2 + O2
a) How many moles of
NO2 are produced when 1 mole of Ca (NO3)
decomposes?
b) What volume of
O2 at S T P will be produced on heating 65 6g of 2Ca
(NO3)?
c) Find out the mass of CaO
formed when 65 6g of Ca (NO3) is heated?
d) Find out the mass of Ca
(NO3), required to produce 5 moles of gaseous
products?
e) Find out the mass of Ca
(NO3) required to produce 44 8 L of NO2 at S
T P ?

na · Accepted Answer

a It is clear from the equation that two moles of 
Ca (NO3) produces produce 4 moles of

NO2

So one
mole of 
Ca (NO3) will give 2 moles of

NO2
on
decomposition

b

Molar
mass of

Ca
(NO3)
=102 08 g

Number of moles of O2 produces by 65 6 g

Ca (NO3) =
65 6/102 08 = 0 6426
At STP volume of 1 mole O2 = 22 4 L
Volume of 
0 6426 mole = 0 6426 x 22 4 = 14 4 L

C One mole

Ca (NO3) gives one mole CaO
i e
102 08 g

Ca (NO3) gives 56 08 g CaO
65 6 g

Ca (NO3) will give (56 08/102 08) x 65 6 g CaO = 36
388 g CaO

D One mole of

Ca (NO3)
gives 5 mole of gases products i e 4 mole OF 
NO2 and
one mole O2
Mass of one mole

Ca (NO3) =
40+14+ 3 x 16 = 102 08 g
E 44 8 L NO2 at STP = 2 mole NO2
Mass of 
Ca
(NO3)
required to produce 44 8 L NO2 
at STP = Mass of 1 mole of Ca
(NO3) =
102 8 g