The equation of circle which touches both the axes and the line 4x+3y=12 and lies in the first quadrant is (x-c)^2+(y-c)^2 =c^2 where c is

THE CENTRE LIES ON THE LINE Y=X
FIND THE PERPENDICULAR DISTANCE OF THE CENTRE FROM THE CENTRE TO LINE THIS IS RADIUS. AS IT TOUCHES THE AXES THEREFORE THE RADIUS IS EQUAL TO X=Y
FINALLY THE COORDINATES OF THE CENTRE WILL BE (-6,-6)
THEREFORE c=-6