The equation of motion of a projectile is y =12x - 3/4x^2.Given that g=10 ms what is the range of the projectile Share with your friends Share 6 Ved Prakash Lakhera answered this Given eqn of projectile motion, y = 12 x - 3 x24. Comparing this eqn with standard eqn of projectile motion. y = x tanθ - g x22 u2 cos2θ.We get tanθ = 12 and g2 u2 cos2θ=34 or u2 cos2θ = 10×42×3. or u cosθ = 2 23 . tanθ = sinθcosθ = 12 or u sinθ =u cosθ×12 or u sinθ = 24 23.Now the range of projectile = u cosθ× 2u sinθ/g = 2 23 × 2× 24 23 /10 = 64/3=21.33 m 7 View Full Answer
