The equation of the line bisecting the obtuse angle between y - x = 2 and 2y + x = 5 is (y-x-2)/(2)1/2 = (x+2y-5)/n. Find n ?

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Please find below the solution to the asked query :

y-x=22y+x=5a1a2+b1b2=-11+12=1>0Hence positive sign in 1 will give obtuse angled bisectory-x-2-12+12=x+2y-512+22y-x-22=x+2y-55Comparing with y-x-22=x+2y-5nSo ,n=5   ANS...
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