the equation of the line passing through the point of intrection of the lines x+y-5=0,2x-y+4=0 and having intercepts numerical equal - Maths - Straight Lines

Question

the equation of the line passing through the point of intrection of
the lines x+y-5=0,2x-y+4=0 and having intercepts numerical equal
is?

Manbar Singh · Accepted Answer

The given equations are :x + y = 5   
12x - y = -4    
2Adding 1 and 2, we get3x = 1⇒x = 13Now, put x = 13 in 1, we gety = 5 - 13 = 143So, point of intersection is 13, 143Now, equation of the line in intercept form isxa + yb = 1But a = b, then above equation becomes,x + y = a   
3Since, 3 passes through 13, 143, then13+ 143 = a⇒a = 5Hence, equation of the line is x + y = 5

the equation of the line passing through the point of intrection of the lines x+y-5=0,2x-y+4=0 and having intercepts numerical equal is?