the equation to the locus of a point p for which the distance from p to (-4,0) is double the distance from p to x-axis is?
Hello Krishna Vamsi, let P (x,y) be the movable point
Distance of P from A (-4,0) will be given as AP = {(x +4)^2 + y^2 }^1/2
Distance of P(x,y) from X- axis say PB will by y
Given PA = 2 P B
Or PA^2 = 4 PB^2
{(x +4)^2 + y^2 } = 4 y^2
Or (x +4)^2 - 3 y^2 = 0
Equation to the locus of P will be (x +4)^2 - 3 y^2 = 0
Distance of P from A (-4,0) will be given as AP = {(x +4)^2 + y^2 }^1/2
Distance of P(x,y) from X- axis say PB will by y
Given PA = 2 P B
Or PA^2 = 4 PB^2
{(x +4)^2 + y^2 } = 4 y^2
Or (x +4)^2 - 3 y^2 = 0
Equation to the locus of P will be (x +4)^2 - 3 y^2 = 0