The equilibrium constant for the following redox reaction at 298 K of 1 10 raised to 8 2Fe - Chemistry -

Question

The equilibrium constant for the following redox reaction at 298 K
of 1?10 raised to 8 2Fe raisedto +3 ( aq ) + 2I raised to -1(aq) =
2Fe raised to 2+ (aq) + I2 (s) If the standard reduction potential
of iodine becoming iodide is +0 54V , what is the standard
reduction potential of Fe raised to 3+ by Fe raised to 2+ ?

Arjun Ravindran K · Answer

Thank you for the question
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