The equilibrium constant of the reaction A2 +B2 = 2AB at 100 C is 50 . If one litre fladk containing one mole A2 is connectef to a two litre flask containing two moles B2 then how many moles of AB will be formed at 373k ? Share with your friends Share 28 Nisha Choudhary answered this Send it's answer -16 View Full Answer Deepshikha answered this And is 1.86 7 Surabhi Likhare answered this please explain this ans 8 Kanika Khandelwal answered this Dear student, Equilibrium constant K= [AB]2/[A2][B2] Total volume of flask=1+2=3L [A2]= 1/3=0.33M [B2]=2/3=0.66M Therefore, [AB]2= K*[A2][B2]= 50*0.33*0.66= 10.89 [AB]=3.30M No. of moles of AB= 3.30*3=9.9 moles -12 Vatsal Bhateria answered this Please find this answer 50 A answered this 100/6% 11 +917xxxxxx73 answered this Moles of AB is 1.75 moles -6 Max Payne answered this Since vol is 3lit the concn will be divided by 3 and it will be xsquare not 4xsquare 5 Qwerty answered this 100/6% -3 Bharti Singh answered this ans is 1.868 10 Ritisha Rajput answered this moles of AB = 1.91 0
