The equilibrium constant of the reaction A2 +B2 = 2AB at 100 C is 50 . If one litre fladk containing one mole A2 is connectef to a two litre flask containing two moles B2 then how many moles of AB will be formed at 373k ?

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  • -15
And is 1.86
  • 6
please explain this ans
 
  • 7
Dear student,
Equilibrium constant K= [AB]2/[A2][B2
Total volume of flask=1+2=3L
​[A2]= 1/3=0.33M
[B2]=2/3=0.66M
Therefore, [AB]2= K*[A2][B2]= 50*0.33*0.66= 10.89
[AB]=3.30M
No. of moles of AB= 3.30*3=9.9 moles


 
  • -12
Please find this answer

  • 49
100/6%
  • 12
Moles of AB is 1.75 moles

  • -6
Since vol is 3lit the concn will be divided by 3 and it will be xsquare not 4xsquare
  • 5
100/6%
  • -3
ans is 1.868
  • 10
moles of AB = 1.91   
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