the extremities of the diagonal of a parallelogram are the points (3,-4) and (-6,5). if the third vertex is the point (-2,1), then find the coordinates of the third vertex

 fourth vertex = 3 + (-6) - (-2) , (-4) + 5 - 1

= -1, 0

  • -10
Let P(3,-4) Q(-2,1) R(-6,5) S(α,β)

  • 6
-1,2
  • 0
(-2,1)
  • -2
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