The figure below shows three cylindrical copper conductors along with their face areas and lengths. Compare the
resistance and the resistivity of the three conductors. Justify your answer.
Dear Student,
Here,
Case 1
Length of the wire (L) = L
Resistance (R) = R1
Area of cross section (A) = A
We have by the formula for resistivity
R1 = ρ(L/A)
Case 2,
Length of the wire (L) = L
Resistance (R) = R2
Area of cross section (A) = A
R2 = ρ(3L/A/3)
= ρ(3L/A) x 3
9ρ(L/A)
= 9R1
Case 3,
Length of the wire (L) = L/3
Resistance (R) = R3
Area of cross section (A) = 3A
R3 = ρ(L/3/3A)
= ρ(L/3) x 1/3A
= 1/9ρ(L/A)
= 1/9 R1
So, in all these cases the Resistance will change as R1, R2 (9R1) and R3 (1/9 R1)
R2 > R1 > R3
Also as it is of same material the resistivity remains same.
Hope this information will clear your doubts about the topic.
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