the first emission line in the atomic spectrum of hydrogen in the balmer series appears at-

1. 5R/36 /cm 2.3R/4/cm 3.7R/144/cm 4.9R/400/cm

For the first emission line in Balmer series, n1 = 2 and n2 = 3.
Using Rydberg's formula:
ν¯ =R 1n12-1n22 cm-1   = R 122-132cm-1   = R 14-19cm-1   = 5R36cm-1

Hence, option (1) is correct.

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