the first orbit of H is represented as : Ψ = 1/√pi (Z/a0)3/2 e-Zr/a0, where a0 is the bohr radius - Chemistry - Structure of Atom

Question

the first orbit of H is represented as :
Ψ = 1/√pi (Z/a0)3/2
e-Zr/a 0 , where a0 is
the bohr radius the probability of finding the electron at a
distance r, from the nucleus in the region dV is given as??
plz ans ASAP

Kumar Sarang · Accepted Answer

Probablity of finding an electron is given as : =∫ψψ*dVFor given functionψ=1πZao3/2e-Zr/ao Probability =1πZao3/22∫ e-2Zr/ao dVwheredV =r2sinθ dr dθ dφProbabilty =1πZao3/22∫0a e-2Zr/aor2 dr∫0π sinθ dθ∫02π dφSolving the integral we get =-ao3Z12+12Z-14Z2-14Z3 e-2z
4πApplying approximation12-12Z+14Z2-14Z3 =e2zThus probability =ao3Ze2z
e-2z4π =4πao3Z

the first orbit of H is represented as : Ψ = 1/√pi (Z/a0)3/2 e-Zr/a 0 , where a0 is the bohr radius. the probability of finding the electron at a distance r, from the nucleus in the region dV is given as?? plz ans.. ASAP.

the first orbit of H is represented as :

Ψ = 1/√pi (Z/a₀)^3/2 e^-Zr/a _⁰, where a₀ is the bohr radius. the probability of finding the electron at a distance r, from the nucleus in the region dV is given as??

plz ans.. ASAP.