The force f =fi^ on a particle of mass 2 kg moving along the x axis is given in the fig as a function of its position x; the particle is moving with a velocity of 5m/s along the x axis at x =0 what is the kinetic energy of the particle at x=8
Initial velocity along X axis, Ux = 5 m/s
Acceleration upon the action of force = F cos θ / mass
= 10 √2 x (1/√2) / 2
= 5 m/s2.
Now, Vx = Ux + axt
Vx = 5 + [5 x 3]
Vx = 20m/s
Now, displacement alonf Y axis also needs to be considered as the force will displace the body from its straight line path.
So, Vy = Uy + ayt
Vy = 0 + 5 x 3 = 15 m/s
Now, resultant V = √(Vx2 + Vy2)
= √(202 + 152)
Thus,velocity after 3 sec = 25 m/s.