~~The frequency changes by 10% as a sound source approaches a stationary observer with constant speed Vs. What would be the % change in the frequency as the source recedes the observer with same speed (Vs < V) ? 1) 10.5% 2) 8.5% 3) 4.5% 4) 1.5%

Case I: Source approaches a stationary observerf'=vv-vsff'f=vv-vsf'f-1=vv-vs-1f'-ff=vsv-vs0.1=vsv-vsvs=0.1v-0.1vs1.1vs=0.1vv=11vsCase II: Source recedes the stationary observerf'=vv+vsff'f=vv+vsf'f-1=vv+vs-1f'-ff=-vsv+vs            =-vs11vs+vs            =-8.5%Here, - sign indicates decrease in frequency.Ans: Option - (2)

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