The fringe width in Young's experiment, when the separation between the slits is 0.5mm and the distance of the screen from the slits is 1.5m, is 1.8mm. Find the path difference between the interfering waves at the position of the first order maximum Share with your friends Share 6 Rohit Babu answered this Dear Student,Given,D=1.5m ,d=.5×10-3m,x=1.8×10-3Path difference,Δp=xdD=1.8×10-3×.5×10-31.5=6×10-7m=60μmRegards.. 4 View Full Answer