The given figure represents a circle with centre O and arc AB=arc AC. What is the measure of angle OCB.​
If we use the anglesum property of trianlge ABC, we get the angle OCB to be 35 degree. However, if we use the theorem, angle subtended by a chord at the centre is twice the angle subtended by it at any point on the circumference and then use anglesum property of triangle OBC, we get angle OCB to be 20 degree. How is it possible?

By using theorem, angle subtended by a chord at the centre is twice the angle subtended by it at any point on the circumference
BOC=2BACBOC=140 degreeNow in triangle BOC, OB=OC=radiusSo OBC=OCB=180-1402=20 degreeNow We know only about angle A and angle ABO so we cannot use angle sum property in triangle ABC.

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How can we use the angle sum property of triangle abc to get angleOCB to be 35 degree????//??
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It is given that arc AB=arc AC. So, chord AB=chord BC.
Therefore, 255=20+ = 35
But if we use Central Angle Theorem,
​ = 2 x 70
= 140
OB = OC (Radii of same circle)
Using Anglesum Property,
140 + 2 = 20
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