The given statement can be written in the form of if-then as follows.
Ifaandbare real numbers such thata2=b2, thena=b.
Letp:aandbare real numbers such thata2=b2.
q:a=b
The given statement has to be proved false. For this purpose, it has to be proved that ifp, then ∼q. To show this, two real numbers,aandb, witha2=b2are required such thata≠b.
Leta= 1 andb= 1
a2= (1)2= 1 andb2= ( 1)2= 1
∴a2=b2
Dear Student ,
The query asked by you is not clear and appears to be incomplete . Please check your query and repost it so we can help you out .
Here you can understand this in following way :
If a = b then a2 = b2.
It is always true .
But if a2 = b2. then it is not necessary that a = b .
For example (3)2 = (-3)2 , but (3) != (-3)
If your query is still unclear , please get back to us .
The query asked by you is not clear and appears to be incomplete . Please check your query and repost it so we can help you out .
Here you can understand this in following way :
If a = b then a2 = b2.
It is always true .
But if a2 = b2. then it is not necessary that a = b .
For example (3)2 = (-3)2 , but (3) != (-3)
If your query is still unclear , please get back to us .